12c^2+29c-8=0

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Solution for 12c^2+29c-8=0 equation:


Simplifying
12c2 + 29c + -8 = 0

Reorder the terms:
-8 + 29c + 12c2 = 0

Solving
-8 + 29c + 12c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-8 + -3c)(1 + -4c) = 0

Subproblem 1

Set the factor '(-8 + -3c)' equal to zero and attempt to solve: Simplifying -8 + -3c = 0 Solving -8 + -3c = 0 Move all terms containing c to the left, all other terms to the right. Add '8' to each side of the equation. -8 + 8 + -3c = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -3c = 0 + 8 -3c = 0 + 8 Combine like terms: 0 + 8 = 8 -3c = 8 Divide each side by '-3'. c = -2.666666667 Simplifying c = -2.666666667

Subproblem 2

Set the factor '(1 + -4c)' equal to zero and attempt to solve: Simplifying 1 + -4c = 0 Solving 1 + -4c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -4c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -4c = 0 + -1 -4c = 0 + -1 Combine like terms: 0 + -1 = -1 -4c = -1 Divide each side by '-4'. c = 0.25 Simplifying c = 0.25

Solution

c = {-2.666666667, 0.25}

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